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NFCCG: Rodgers vs. Brady @ Lambeau Field
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<blockquote data-quote="Dantés" data-source="post: 896907" data-attributes="member: 12283"><p>Here's an interesting angle to this game.</p><p></p><p>The Packers' style on offense and defense really limits the number of drives in a game. </p><p></p><p>They lead the league in length of drive, and they lead the league in % of drives ending in points. </p><p></p><p>On defense, they're 14th in length of drive allowed and 16 in % of drives ending in points, but they are really good at avoiding big plays. </p><p></p><p>Sharp Football defines an explosive run as one going for 10+ yards, and an explosive pass as one going for 15+ yards. By their numbers, the Packers are tied for 10th best in explosive run % allowed, and tied for 2nd best in explosive pass % allowed. So they will give up yards and points, but not usually in big shots. </p><p></p><p><strong>What this all boils down to is the fact that the Packers have had the 3rd least amount of drives on offense (161-- dead last is 157), and they've faced the 2nd least amount of drives on defense (158-- dead last is 157). </strong></p><p></p><p>While every week/opponent's gameplan is surely different, I think the basic calculus is the same every week: the Packers are going to count an having 8-10 drives, while facing 8-10 drives, and they bet that more of their drives will end in points than the opponents. </p><p></p><p>This would explain the defensive gameplans that we all find so frustrating at times. I believe the design is to force longer, more deliberate drives, as this prevents quick scores and gives the defense more chances to make a play that would force a drive to end in a kick, punt, or turnover. </p><p></p><p>The Bucs have run the 8th most drives in football this year. They're used to playing a lot faster. If the Packers can successfully slow them down, as they have so many other teams, they should only need to get 3-5 stops (by which I mean drives that end in anything other than a TD) to win.</p></blockquote><p></p>
[QUOTE="Dantés, post: 896907, member: 12283"] Here's an interesting angle to this game. The Packers' style on offense and defense really limits the number of drives in a game. They lead the league in length of drive, and they lead the league in % of drives ending in points. On defense, they're 14th in length of drive allowed and 16 in % of drives ending in points, but they are really good at avoiding big plays. Sharp Football defines an explosive run as one going for 10+ yards, and an explosive pass as one going for 15+ yards. By their numbers, the Packers are tied for 10th best in explosive run % allowed, and tied for 2nd best in explosive pass % allowed. So they will give up yards and points, but not usually in big shots. [B]What this all boils down to is the fact that the Packers have had the 3rd least amount of drives on offense (161-- dead last is 157), and they've faced the 2nd least amount of drives on defense (158-- dead last is 157). [/B] While every week/opponent's gameplan is surely different, I think the basic calculus is the same every week: the Packers are going to count an having 8-10 drives, while facing 8-10 drives, and they bet that more of their drives will end in points than the opponents. This would explain the defensive gameplans that we all find so frustrating at times. I believe the design is to force longer, more deliberate drives, as this prevents quick scores and gives the defense more chances to make a play that would force a drive to end in a kick, punt, or turnover. The Bucs have run the 8th most drives in football this year. They're used to playing a lot faster. If the Packers can successfully slow them down, as they have so many other teams, they should only need to get 3-5 stops (by which I mean drives that end in anything other than a TD) to win. [/QUOTE]
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NFCCG: Rodgers vs. Brady @ Lambeau Field
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