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Ron wolf says money brought Reggie White to Green Bay
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<blockquote data-quote="Poppa San" data-source="post: 598797" data-attributes="member: 2547"><p>Not in new math:</p><p>Let <strong>a = 1</strong> and <strong>b = 1</strong>. Therefore <strong>a = b</strong>, by substitution.</p><p>If two numbers are equal, then their squares are equal, too: <strong> a^2 = b^2</strong>.</p><p>Now subtract b^2 from both sides (if an equation is true, then if</p><p>you subtract the same thing from both sides, the result is also</p><p>a true equation) so: <strong>a^2 - b^2 = 0</strong>.</p><p>Now the lefthand side of the equation can be factored into (a-b)*(a+b).</p><p>If you don't believe me, then try multiplying it out carefully,</p><p>and you will see that it's correct. So: <strong>(a-b)*(a+b) = 0</strong>.</p><p>Now if you have an equation, you can divide both sides by the same</p><p>thing, right? Let's divide by (a-b), so we get: <strong>(a-b)*(a+b) / (a-b) = 0/(a-b)</strong>.</p><p>On the lefthand side, the (a-b)/(a-b) simplifies to 1, right?</p><p>and the righthand side simplifies to 0, right? So we get: <strong>1*(a+b) = 0</strong>,</p><p>and since 1* anything = that same anything, then we have: <strong>(a+b) = 0</strong>.</p><p>But a = 1 and b = 1, so: 1<strong> + 1 = 0, or 2 = 0</strong>.</p><p>Now let's divide both sides by 2, and we get: <strong>1 = 0</strong>.</p><p>Then we add 1 to both sides, and we get:</p><p><strong>1 + 1 = 1</strong>.</p></blockquote><p></p>
[QUOTE="Poppa San, post: 598797, member: 2547"] Not in new math: Let [B]a = 1[/B] and [B]b = 1[/B]. Therefore [B]a = b[/B], by substitution. If two numbers are equal, then their squares are equal, too: [B] a^2 = b^2[/B]. Now subtract b^2 from both sides (if an equation is true, then if you subtract the same thing from both sides, the result is also a true equation) so: [B]a^2 - b^2 = 0[/B]. Now the lefthand side of the equation can be factored into (a-b)*(a+b). If you don't believe me, then try multiplying it out carefully, and you will see that it's correct. So: [B](a-b)*(a+b) = 0[/B]. Now if you have an equation, you can divide both sides by the same thing, right? Let's divide by (a-b), so we get: [B](a-b)*(a+b) / (a-b) = 0/(a-b)[/B]. On the lefthand side, the (a-b)/(a-b) simplifies to 1, right? and the righthand side simplifies to 0, right? So we get: [B]1*(a+b) = 0[/B], and since 1* anything = that same anything, then we have: [B](a+b) = 0[/B]. But a = 1 and b = 1, so: 1[B] + 1 = 0, or 2 = 0[/B]. Now let's divide both sides by 2, and we get: [B]1 = 0[/B]. Then we add 1 to both sides, and we get: [B]1 + 1 = 1[/B]. [/QUOTE]
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Ron wolf says money brought Reggie White to Green Bay
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