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Football gonna become unwatchable
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<blockquote data-quote="PFanCan" data-source="post: 509611" data-attributes="member: 1989"><p>Being "overly simplistic", IMO, is stating a correct fact but leaving out the complicated details. In this case, stating that E=Mc2 has something to do with player collisions is "simply incorrect".</p><p> </p><p>An object moving twice as fast certainly has four times more energy, as you illustrate with the kinetic energy equation. Agreed. Energy is not conserved here, though. This just means that four times more energy is lost when the collision occurs and the system velocity goes to zero. It is largely dissipated through heat and noise. Some is transferred to the tackler in the form of heat and "rebound" velocity during the course of the tackle, but...</p><p> </p><p>The energy equation has nothing to do with calculating how much force (hence "hurt") it takes to stop a moving object in an inelastic collision. The only equations that apply are momentum and impulse.</p><p> </p><p style="margin-left: 20px"><em>Momentum = Mass of moving object * velocity of moving object</em></p> <p style="margin-left: 20px"></p> <p style="margin-left: 20px"><em>Impulse = Force applied by tackler * time elapsed during impact</em></p><p></p><p>And... using Hypon's suggestion, we can throw in Pressure as well:</p><p> </p><p style="margin-left: 20px"><em>Pressure = Force / Area of contact</em></p><p></p><p>In conclusion, keeping all things equal and calling "force" or "pressure" = "hurt":</p><ol> <li data-xf-list-type="ol">If one doubles the mass, the hurt is doubled</li> <li data-xf-list-type="ol">If one doubles the velocity, the hurt is doubled</li> <li data-xf-list-type="ol">If one halves the elapsed time of the impact, the hurt is doubled</li> <li data-xf-list-type="ol">If one halves the surface area of contact, the hurt is doubled</li> </ol><p>Now, my head really hurts.</p></blockquote><p></p>
[QUOTE="PFanCan, post: 509611, member: 1989"] Being "overly simplistic", IMO, is stating a correct fact but leaving out the complicated details. In this case, stating that E=Mc2 has something to do with player collisions is "simply incorrect". An object moving twice as fast certainly has four times more energy, as you illustrate with the kinetic energy equation. Agreed. Energy is not conserved here, though. This just means that four times more energy is lost when the collision occurs and the system velocity goes to zero. It is largely dissipated through heat and noise. Some is transferred to the tackler in the form of heat and "rebound" velocity during the course of the tackle, but... The energy equation has nothing to do with calculating how much force (hence "hurt") it takes to stop a moving object in an inelastic collision. The only equations that apply are momentum and impulse. [INDENT][I]Momentum = Mass of moving object * velocity of moving object[/I] [I]Impulse = Force applied by tackler * time elapsed during impact[/I][/INDENT] And... using Hypon's suggestion, we can throw in Pressure as well: [INDENT][I]Pressure = Force / Area of contact[/I][/INDENT] In conclusion, keeping all things equal and calling "force" or "pressure" = "hurt": [LIST=1] [*]If one doubles the mass, the hurt is doubled [*]If one doubles the velocity, the hurt is doubled [*]If one halves the elapsed time of the impact, the hurt is doubled [*]If one halves the surface area of contact, the hurt is doubled [/LIST] Now, my head really hurts. [/QUOTE]
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